Successive Over Relaxation Calculator
Free online successive over relaxation calculator. Enter your values and get instant results with the formula, step-by-step working, a worked example and FAQs — everything runs locally in your browser on Calcton, no signup required.
中文版:SOR 松弛迭代计算器
原理:SOR(逐次超松弛)在高斯-赛德尔步与旧值之间做加权平均 x⁽ᵏ⁺¹⁾ = (1 − ω)x⁽ᵏ⁾ + ω·GS 步;ω = 1 退化为高斯-赛德尔,ω < 1 叫低松弛(更稳更慢),1 < ω < 2 叫超松弛(通常更快),ω ≥ 2 对任何矩阵都发散。
步骤:① 输入矩阵与右端向量;② 设定 ω;③ 对比不同 ω 下的轮数,找经验最优值。
示例:对 A = [[4, 1, 0], [1, 5, 1], [0, 1, 4]]、b = [6, 14, 14],ω = 1 时与高斯-赛德尔完全一致,ω = 1.2 时 17 轮收敛到 10⁻¹⁰,而 ω = 2.1 会数值发散——Ostrowski-Reich 定理的现场演示。
注意事项:最优 ω ≈ 2/(1 + √(1 − ρ²))(ρ 为雅可比谱半径),但依赖未知量 ρ,实践中靠试算;本矩阵本身收敛很快,超松弛收益小——SOR 的威力在大型差分方程系数阵上。
相关:高斯-赛德尔计算器是 ω = 1 的特例;雅可比计算器给出谱半径的参照;共轭梯度类方法在大规模问题上常优于 SOR。
How to use the Successive Over Relaxation Calculator
- Fill in the inputs with your own numbers — every field shows what it expects.
- The result updates instantly as you type; no "Calculate" click needed.
- Read the result card for the main figure, the step-by-step formula, and practical notes.
Frequently asked questions
Is the Successive Over Relaxation Calculator free?
Yes — all math calculators on Calcton are free, with no sign-up required. Your inputs are processed in your browser and never sent to a server.
Is there a Chinese version of this tool?
Yes. Use the Chinese version link above — it is the same calculator with the interface in Simplified Chinese.
References
Formulas and benchmarks used by this calculator follow these published sources.
KevinContent LeadCalcton Editorial Team · Last updated 2026-10-04
Kevin maintains Calcton's formula verification and content: every calculator cites the standard it implements, worked examples are recomputed programmatically, and health benchmarks follow WHO and international guidelines.
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